the measure of one angle of a the parallelogram is 70 degree what are the measures of the remaining angles
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Let, ABCD be the parallelogram whose one angle is 70°.
Let angle ABC=70°
So, angle ABC=angle ADC(opp. angles of a parallelogram are equal)
=>angle ADC=70°
And, angle ABC+angle BCD=180°(adjacent angles of a parallelogram are supplementary)
=>70°+angle BCD=180°
=>angle BCD=180°-70°
=110°
So,angle BCD=angle DAC(opp. angles of a parallelogram are equal)
=>angle DAC=110°
Therefore, all the angles of the parallelogram are 70°,110°,70°&110°.
Let angle ABC=70°
So, angle ABC=angle ADC(opp. angles of a parallelogram are equal)
=>angle ADC=70°
And, angle ABC+angle BCD=180°(adjacent angles of a parallelogram are supplementary)
=>70°+angle BCD=180°
=>angle BCD=180°-70°
=110°
So,angle BCD=angle DAC(opp. angles of a parallelogram are equal)
=>angle DAC=110°
Therefore, all the angles of the parallelogram are 70°,110°,70°&110°.
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