Math, asked by bhanu90, 1 year ago

the measure of the angles of a pentagon are (x-5)°,(x-6)°,(2x-7)°,x° and(2x-2)°.find tbe value of x.

Answers

Answered by bhoomi81

sum of angles of a Pentagon =540degrees
x-5+x-6+2x-7+x+2x-2=540
x+x+2x+2x-20=540
7x-20=540
7x= 540+20
7x=560
x=560/7=80.

Therefore x=80 degrees.

bhoomi81: is the answer correct

amairasingh: no

bhoomi81: why??

amairasingh: yhhhh

amairasingh: sorry

bhoomi81: OK

amairasingh: but now it is also incomplete because uh have to find all the angles of Pentagon

bhoomi81: it isn't mentioned in the question

amairasingh: it is mentioned

amairasingh: if not mentioned then we always have to be find all angles

Answered by amairasingh

=x-5 + x-6 + 2x-7 + x + 2x-2 = 540
= 7x -20 =540
= 7x = 540 +20
= 7x = 560
= x = 560/7
= x = 80
= x-5 = 80-5
= 75
= x-6= 80-6
= 74
= 2x-7= 2×80-7
=160-7
= 153
= x = 80
=2x-2= 2×80-2
= 160-2
= 158
*hope it helps uh*

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