The measure of the height AD of a AABC with respect to the base BC
is 4 cm. P is a point on BC such that BP = 3 cm. and arAABP = arAAPC.
Find the measure of PC.
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2
Answer:
96 cm
Step-by-step explanation:
(
EF
BC
)
2
=
ArΔDEF
ArΔABC
(
4
3
)
2
=
ArΔDEF
54
Ar(ΔDEF)=54×
9
16
=96cm
2
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