The measure of two adjacent angle of a parallelogram are in ratio 3ratio2. Find the measures of each angle?
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let 3:2 be 3x and 2x respectively.opposite angles of a parallelogram are equal.
so remaining angles will also be equal that is 3x and 2 x
sum of all sides of parallelogram = 360°
3x+2x+3x+2x=360°
10x = 360°
x =360°/10°
x=36°
3x = 3 (36°)= 108°
2x = 2 (36°) = 72°
ans...the measure of each angle of the parallelogram is 108° , 72° ,108°,72°.
so remaining angles will also be equal that is 3x and 2 x
sum of all sides of parallelogram = 360°
3x+2x+3x+2x=360°
10x = 360°
x =360°/10°
x=36°
3x = 3 (36°)= 108°
2x = 2 (36°) = 72°
ans...the measure of each angle of the parallelogram is 108° , 72° ,108°,72°.
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