The measure of two adjacent angles are in the ratio 3:2. Find the measure of each of the angle of the Parallelogram
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Let two adjacent angles A and B of ∥gm ABCD be 3x and 2x respectively.
Since the adjacent angles of a parallelogram are supplementary.
∠A+∠B=180o
⇒3x+2x=180o
⇒5x=180o
⇒x=5180o=36o
∴∠3×36o=108o
and, ∠B=2×36o=72o
Since the opposite angles are equal in a parallelgram, therefore, ∠C=∠A=108o and ∠D=∠B=72o
Hence, ∠A=108o,∠B=72o,∠C=108o and ∠D=72o
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Measures = x
Ratio = 3:2
Let first angle be A = 3x
Let second angle be B = 2x
Sum of Angles of Parallelogram = 180°
Equation = 3x+2x = 180°
= 5x = 180°
= x = 180/5 = 36
A = 3x = 3×36 = 108°
B = 2x = 2×36 = 72°
The opposite sides are equal in a parallelogram
Opposite of A = C = 108°
Opposite of B = D = 72°
Final Answer = A - 108°, B - 72°, C - 108°, D - 72°.
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