Question

the measure of two adjacent side of a rectangle are in the ratio of 11:10if the perimeter of the rectangle is 84cm find its area

Answer 1

perimeter of rectangle = 2(l+b) 

length = 11x

breadth = 10x

according to the sum ,

2 (11x+10x) =  84

22x +20x = 84

42x = 84

x = 84/42

x = 2

length = 11x= 11 * 2= 22

breadth = 10x = 10 * 2 = 20

area of rectangle = l*b

22*20 = 440sq.cm

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THANKS 


-P.Priyamvatha