Question

the measure of two adjacent sides of a rectangle are in the ratio of 11:10.if the perimeter of the rectangle is 84 cm ,find its area

Answer 1

$<b><i>$

Hey mate!

Here is your answer > >

Let the adjacent sides of a rectangle be 11x and 10x

Perimeter of rectangle = 84 cm

But perimeter of rectangle = 2 (l+b)

2(l+b)=84

2 (11x+10x)=84

21x=42

x=2

Length=11x=22 cm

Breadth=10x=20 cm

Area=l×b=22×20=440 cm^2

Hope it helps!

Thankyou ☆ ☆

Answer 2

$\bf{\underline{Question:-}}$

the measure of two adjacent sides of a rectangle are in the ratio of 11:10.if the perimeter of the rectangle is 84 cm ,find its area.

$\bf{\underline{Given:-}}$

• Measure of two adjacent side is 11 : 10
• perimeter is 84cm

$\bf{\underline{To\:Find:-}}$

• Area = ?

$\bf{\underline{Formula:-}}$

$\sf{\boxed{\pink{Perimeter\:of\: rectangle=2(Lenght+Breadth)}}}$

$\sf{\boxed{\pink{Area\:of\: rectangle=Lenght×Breadth}}}$

$\bf{\underline{Solution:-}}$

• Let all adjacent side ratio be in the form of X

So,

Side will be = 11x and 10x

• By Perimeter Formula

$\sf :→ 2(L + b ) = 84$

$\sf :→ 2 ( 11x + 10x ) =84$

$\sf :→ 2 ( 21x ) = 84$

$\sf :→ 42x = 84$

$\sf :→ x = \dfrac{84}{42}$

$\bf :→ x = 2$

$\bf{\underline{Now:-}}$

• Substituting value of X in adjacent sides

$\sf :→ First\: adjacent\:side\:is\:11x = 11 × 2 = 22cm$

$\sf :→ Second\: adjacent\:side\:is\:10x= 10×2=20cm$

$\bf{\underline{Finding\:Area\:of\: Rectangle:-}}$

• By Area of rectangle Formula.

$\sf :→ Area = Length × Breadth$

$\sf :→ Area = 22 × 20$

$\sf :→ Area = 440cm^2$

$\bf{\underline{Hence:-}}$

• The area of rectangle is 440cm²