Question

the measure of two adjecent angles of a parallelogram are in the ratio 3:2. find the measure of each of the angles of the parallelogram.

Answer 1

let the adjacent angles be 3x° and 2x°.
3x°+2x°=180°(sum of adjacent angles of a llgm is 180°
5x°=180°
x°=(180/5)°
x°=36
therefore the angles are 108° and 72°

Answer 2

Adjacent angles of a parallelogram are supplementary
3x+2x=180
5x=180
x=180/5
x=36
3x=3*36=108
2x=2*36=72
first angle measure=108
second angle measure=72
third angle measure=108{opposite angles of paralleogram is equal}
fourth angle=72{"""""}