The measure of two angles of a triangle are in the ratio 7:11. If the sum of these two angle is equal to the third angle, find the measurea of all the angles of the triangle.
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Answered by
5
two angles ratio=7:11
let,
two ratios be 7x and 11x
given,
third angle=7x+11x=18x
we know that,
Sum of three angles=180°
⇒7x+11x+18x=180°
⇒36x=180°
⇒x=5°
∴3 angles of a triangle 35°,55° and 90°
let,
two ratios be 7x and 11x
given,
third angle=7x+11x=18x
we know that,
Sum of three angles=180°
⇒7x+11x+18x=180°
⇒36x=180°
⇒x=5°
∴3 angles of a triangle 35°,55° and 90°
Answered by
3
let the first angle A = 7x
second angle B =11x
third angle C =18x
sum of the angles in a triangle 180degree
A+B+C =180
7x+11++18x =180
36x=180
x = 180/36
x =5
therefore
A= 7x=7*5=35
B= 11x =11*5=55
C =18x=18*5=90
second angle B =11x
third angle C =18x
sum of the angles in a triangle 180degree
A+B+C =180
7x+11++18x =180
36x=180
x = 180/36
x =5
therefore
A= 7x=7*5=35
B= 11x =11*5=55
C =18x=18*5=90
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