The measurement of radius of a sphere is 2.5 cm.
(i) Find the maximum possible error
in this
measurement.
(ii) Find the percentage error in the calculation of its
surface area and volume.
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surface area of sphere
A=4πr
2
a=4×3.14×(2.1)
2
=55.4cm
2
A=4πr
2
A=4×3.14×(2.1)
2
=55.4cm
2
\\
A
ΔA
=2×
r
Δr
ΔA=2×
r
Δr
×A
=2×
2.1
0.5
×55.4
=26.4cm
2
Surface area =(55.4±26.4)cm
2
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