Question

What is the mass of copper sulphate present in 500 ml of 25% solution of it at 298 K.​

Answer 1

100 g of dilute solution of CuSO
4
​
contain
=1.2×10=12.0gCuSO
4
​

Mass of water present in dilute solution
=(100−12)=88g
To saturate 100 g of water, CuSO
4
​
required =25g
So, to saturate 88 g of water, CuSO
4
​
required =
100
25
​
×88=22g
Thus, the mass of CuSO
4
​
to be added to 100 g of dilute solution to saturate it =(22−12)=10g.

Mark me as brainlist