The measures of a text book are 22 cm x 11 cm x 3 cm. It is to be covered with a brown paper. If each book requires 164 cm² of more paper for folding, how much paper is required to wrap 85 such text books?
Answers
Solution:-
we have,
Length of a text book = l = 22 cm,
Width of a text book = b = 11 cm,
Height of a text book = h = 3 cm,
The text book is covered with a paper only on three faces, that are bottom, top and back.
we have,
Area of the bottom = lxb
=22x11 cm² = 242 cm²
Area of the top = Area of the bottom
= 242 cm²
Area of the back face =lxh
= 22x3 = 66 cm²
Area of the paper required for folding
= 164 cm²
∴ Area of the paper required for one text book
= (242+ 242+66+164)cm² = 714cm²
Hence, Area of paper needed for 85 such text
books' =714x85 cm² =60690 cm².
GIVEN :-
- Length = 22 cm.
- Breadth = 11 cm.
- Height = 3 cm.
TO FIND :-
- The paper is required to wrap 85 such text books
SOLUTIONS :-
➳ Area of three sides of text book = (lb + lb + lh)
➳ Area of three sides of text book = 22*11 + 22*11 + 22*3
➳ Area of three sides of text book = 242 + 242 + 66
➳ Area of three sides of text book =550 cm².
Now,
➳ Area of brown paper = Area of three sides of Text book + 164 cm²
➳ Area of brown paper = 550 cm² + 164 cm².
➳ Area of brown paper = 714 cm².
Now,
➳ Area of 85 text books = 714*85
➳ Area of 85 text books = 60690 cm².