The measures of exterior angles, formed by producing each side of a hexagon in order are 4x, 2x+6, 3x-1, 5x-9,x+9and2x-2
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What we are required to find..
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In A Haxagon Each Of Its Exterior Side Is Produced And Angle Formed Are 4x , 2x+6,3x-1,5x-9, X + 9 And 2x-2
Now We Need To Find Measures OF Each Exterior Angle.
The Exterior Angle That Are Given Are ...
Now We Need To Find Measures of all angle.
So For That Follow This Simple Steps ....
1 ) We know that....
Theorem States That In Any Polygon With Any Side Sum Of Their Exterior
Angle Will Always Add Upto 360°.
So Now According to this statement we have
So Now Open The Bracket And Compare The Like Terms ..
We Have..➡️
That is ➡️
Now Taking 3 To Rhs We Have ➡️
That is ➡️
Now taking 17 to RHS we have ➡️
So Now We know the value of X
2) So Now Put This Value Of X In Each Angle .
Angle 1 = 4x ➡️ 4 × 21 = 84°
Angle 2 = 2x +6 ➡️ 2 × 21 + 6 = 48°
Angle 3 = 3x-1➡️3 × 21 -1 = 62°
Angle 4 = 5x -9➡️5 × 21 -9= 96°
Angle 5 = X + 9➡️ 21 +9 = 30°
Angle 6 = 2x- 2➡️2 × 21 - 2 = 40°
Hence The Required Answer Is .....
84 ° , 48° , 62° , 96° , 30° And 40°
Thought of the day.....
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