the measures of the opposite angles of a parallelogram are (3x-2) degree and (50-x) degree.find the measure of each angle of the parallelogram
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Given measures of the opposite angles of a parallelogram are (3x-2) and (50-x)
We know that opposite angles of a parallelogram are equal
⇒ 3x-2 = 50-x
⇒4x=52
⇒x=13 .
the angles are : (3×13)-2 = 39-2 = 37 degrees
50-13 = 37 degrees .
We know that opposite angles of a parallelogram are equal
⇒ 3x-2 = 50-x
⇒4x=52
⇒x=13 .
the angles are : (3×13)-2 = 39-2 = 37 degrees
50-13 = 37 degrees .
harshitchandigarh:
You are wrong. Sum of opposite angles of a parallelogram is not 180º. Also, angles can't be negative.
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Opposite angles of a parallelogram are equal. Use this as a hint to solve the problem. Anyway, I'm also solving it for you.
3x-2=50-x
=> x=13º
Angles are --> 1) 37º
2) 143º
3) 37º
4) 143º
[Because Adjacent sides of a parallelogram are supplementary.]
3x-2=50-x
=> x=13º
Angles are --> 1) 37º
2) 143º
3) 37º
4) 143º
[Because Adjacent sides of a parallelogram are supplementary.]
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