Question

the measures of two angles of a triangle are 78 degree and 62 degree find the measure of the third angle​

Answer 1

in ∆ABC

let the measure of angle A =78° and measure of angle B=62°

angle A+angleB+angleC=180°

78+62+angleC=180

140=+angleC=180

angle C=180-140

=40°

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Answer 2

angle1+angle2 +angle3=180°

78°+62°+angle 3=180°

140°+angle3=180°

angle3=180°-140°

angle3=40°

i hope it will help