Question

the median of first 10 prime numbers​

Answer 1

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FIRST 10 PRIME NUMBERS ARE

2 3 5 7 11 13 17 19 23 29

n=10

n=even therefore

$( \frac{n}{2} )th$

And

$( \frac{n}{2} + 1)th$

terms ARE MEDIAN

therefore

$\frac{10}{2} = 5th$

$(\frac{10}{2} + 1) \\( 5 + 1) \\ 6th$

term

they are 11 and 13
average of this is the MEDIAN 12

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Answer 2

First 10 prime numbers = 2,3,5,7,11,13,17,19,23,29.

Median = 2+3+5+7+11+13+17+19+23+29/10

= 129/10

= 12.9