Question

The median of the following data is 525 find the value of x ,and y if the total frequency is 100

Answer 1

Answer:

that is the answer pls follow me and make this answer brainlist and

Answer 2

$\: \rm\large{\underline{\underline\color{darkblue}{Solution:-}}}$

$\begin{gathered}\begin{gathered}{\large \qquad \boxed{\boxed{\begin{array}{cc} \bf \dashrightarrow \red{\:Given \: n = 100} \\ \\ \rm \: So, \: 76 + x + y = 100 \: i.e. \: x + y = 24 \: (1) \\ \\ \ \bf \: The \: median \: is \: 525 \: which \: lies \: in \: the \: class \: 500 - 600 \\ \\ \rm So, \\ \\ \rm l = 500, \: f = 20 ,\: \: cf = 36 + x \: \: h = 100 \\ \\ \bf \dashrightarrow \red{ Using \: formula} \\ \\ \rm \: Median = l + \frac{ (\frac{n}{2} - cf) }{f} \times h \\ \\ \rm \mapsto \: 525 = 500 + \frac{50 - 36 - x}{20} \times 100 \\ \\ \rm \mapsto \: 525 - 500 = (14 - x) \times 5 \\ \\ \rm \mapsto \: 25 = 70 - 5x \\ \\ \rm \mapsto \: 5x = 70 - 25 = 45 \\ \\ \rm \mapsto \: x = 9 \\ \\ \bf \dashrightarrow \: Therefore, \: from(1), \: we \: get \: 9 + y = 24 \\ \\ \rm \hookrightarrow \fbox \red{y = 15}\end{array}}}}\end{gathered}\end{gathered}$

Note :

• The median of grouped data with unequal class sizes can also be calculated.

@Shivam