Question

The median of the following data is 525.find the value of x and y, if the total frequency is 100 ​

Answer 1

Computation of Median

Class intervalFrequency (f)Cumulative frequency (cf)0-10022100-20057200-300x7+x300-4001219+x400-5001736+x500-6002056+x600-700y56+x+y700-800965+x+y800-900772+x + y900-1000476+x + yTotal = 100We have,

N=∑fi=100

⇒76+x+y=100⇒x+y=24

It is given that the median is 525. Clearly, it lies in the class 500−600 

∴l=500,h=100,f=20,F=36+x and N=100

Now,

Median=i+f2N−F×h

⇒525=500+2050−(36+x)×100

⇒525−500=(14−x)×5

⇒25=70−5x⇒5x=45⇒x=9

Putting x=9 inx+y=24, we get y=15.

Hence, x=9and y=15.

Answer 2

Answer:

x = 9y =15

Step-by-step explanation:

hope it's helps it's step by step explation I'll not know because ye ans mene mere mama se liya h so

SORRY!!