Question

The median of the following data is 525. Find the values of x and y if the total frequency is 100. Class Interval Frequency 0-100 2 100-200 5 200-300 x 300-400 12 400-500 17 500-600 20 600-700 Y 700-800 9 800-900 7 900-1000 4

Answer 1

hey--''

dear------




Example 8The median of the following data is 525. ... Class interval Frequency 0 – 100 2 100 – 200 5 200 – 300 x 300 – 400 12 400 – 500 17 500 – 600 20 600 – 700 y 700 – 800 9 800 – 900 ...:-) ---


CI Fi CF. 0-100 2 2. 100-200 5 7. 200-300 x 7+x. 300-400 12 19+x. 400-500 17 36+x. 500- 600 20 56+x. 600-700 y 56+x+y. 700-800 9 65+x+y. 800-900 7 72+x+y. 900-1000 4 76+x+y. N/2 = 100/2 = 50.:-)

Answer 2

Yup

From Ncert example 8


HELLO DEAR,

MEDIAN IS 525
500 - 600 is median class


we know median =


where, l = lower limit of median class = 500
h = class interval = 100 - 0 = 100
∑f_i = n = 100
cf = cumulative frequency before class median = 36 + x
f = median frequency


525 =

⇒525 = 500 + {50 - (36 + x)} * 5

⇒525 - 500 = {50 - (36 + x)}*5

⇒25/5 = 50 - (36 + x)

⇒36 + x = 50 - 5

⇒x = 45 - 36

⇒x = 9

and
∑f_i = 76 + x + y

100 = 76 + x + y

9 + y + 76 = 100

y = 100 - 85

y = 15


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THANKS