Math, asked by mahekshah09762, 5 months ago

the median of the following frequency distribution is 49 and th
e total frequency is 100.find missing frequencies x and y class 0-10,10-20,20-30,40-50,50-60,60-70,70-80 and frequency 2,6,8,x,20,18,y,14​

Answers

Answered by bhanu123456787
2

Answer:

Class interval Frequency Cumulative Frequency

0−10 5 5

10−20 f

1

5+f

1

20−30 20 25+f

1

30−40 15 40+f

1

40−50 f

2

40+f

1

+f

2

50−60 5 45+f

1

+f

2

N=60

From the table, it can be observed that N=60, then

2

N

=30.

45+f

1

+f

2

=60

∴ f

1

+f

2

=15 -------- ( 1 )

Median of the data is given as 28.5 which lies in interval 20−30.

∴ Median class =20−30

⇒ l=20,cf=5+f

1

,f=20,h=30−20=10.

⇒ Median=l+

f

2

N

−cf

×h

⇒ 28.5=20+

20

30−(5+f

1

)

×10

⇒ 8.5=

2

25−f

1

⇒ 17=25−f

1

∴ f

1

=8

From equation ( 1 ),

⇒ 8+f

2

=15

∴ f

2

=7

∴ The values of f

1

and f

2

are 8 and 7

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0

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