the medians of a triangle ABC intersect at G. show that area triangle AGB equals to 1/3 area of triangle ABC
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Perhaps here we have to show ar. of ∆AGB = 1/2 of ar.∆ABC , if I think right so here is your ans.
As we know that median of triangle divide it into two triangle of equal area
Therefore , ar. ∆AGB = ar.∆ AGC
Now, ar.∆ AGB + ar. ∆ AGC =ar.∆ABC
ar. ∆ AGB+ar.∆AGB =ar. ∆ ABC
2(ar.∆ AGB) = ar.∆ ABC
ar. ∆AGB = 1/2 (ar. ∆ ABC)
As we know that median of triangle divide it into two triangle of equal area
Therefore , ar. ∆AGB = ar.∆ AGC
Now, ar.∆ AGB + ar. ∆ AGC =ar.∆ABC
ar. ∆ AGB+ar.∆AGB =ar. ∆ ABC
2(ar.∆ AGB) = ar.∆ ABC
ar. ∆AGB = 1/2 (ar. ∆ ABC)
Beast748:
wrong brothet
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