Question

The member of the Pythagorean triplet is 4, which of these are the remaining numbers of the triplets.

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Answer 1

Answer:

4 , 15 , 17

Step-by-step explanation:

Pythagorean Triplet = (2m) , (m^2 - 1 ) , ( m^ 2 + 1 ).

So here ,

2m = 4

m = 4/2 ( By Transposing Method )

m = 2

Replace the Value

m^2 - 1 = 4^2 - 1

= 16 - 1 = 15 = 2nd Pythagorean Triplet

m^2 + 1 = 4^2 +1 = 16+1 = 17 = 3rd

Pythagorean Triplet

So Pythagorean Triples =>

4 , 15 , 16