Question

the metal have bcc structure and edge of unit cell is 3.04 angstron then volume of unit cell be

Answer 1

Answer:2.81×10^-23 cm^3

Explanation: volume of unit cell =a^3

= 2.81×10^-29m^3

=2.81×10^-23 cm^3

Please Mark me as Brainliest.

Answer 2

Answer:

The volume of the unit cell in cm^3.

As density = mass / VolumeUse formula,Z= density Na (a)^3 divided by molecular mass Here.

2.81×10^-23 cm^3

Volume of unit cell =a^3=2.81×10^-29m^3=2.81×10^-23 cm^3.