The metal used to recover copper from a solution of copper sulphate is
A. Na
B. Ag
C. Hg
D. Fe
The number of d-electrons in Fe2+ (Z = 26) is not equal to that of
A. p-electrons in Ne(Z = 10)
B. s-electrons in Mg(Z = 12)
C. d-electrons in Fe(Z = 26)
D. p-electrons in CI(Z = 17)
6.
The metallurgical process in which a metal is obtained in a fused state is called
A. smelting
B. roasting
C. calcinations
D. froth floatation
Answers
Answered by
1
1. d
Ag & Hg are less reactive than copper.
adding sodium - it would ignite before it could react.
Fe is more reaction than copper and would displace it to combine with the sulphate ion, thereby separating copper.
2.Answer: D - p-electrons in CI(Z = 17)
No.of d electrons Fe+2 6(3d6)
no.of p electrons in Ne is 6(2p6),
no.of s electrons in Mg is 6(1s2,2s2,3s2)
no.of d electrons in Fe is 6 (d6)
no.of p electrons in Ci is 11(2p6,3p5)
3. smelting
Ag & Hg are less reactive than copper.
adding sodium - it would ignite before it could react.
Fe is more reaction than copper and would displace it to combine with the sulphate ion, thereby separating copper.
2.Answer: D - p-electrons in CI(Z = 17)
No.of d electrons Fe+2 6(3d6)
no.of p electrons in Ne is 6(2p6),
no.of s electrons in Mg is 6(1s2,2s2,3s2)
no.of d electrons in Fe is 6 (d6)
no.of p electrons in Ci is 11(2p6,3p5)
3. smelting
Answered by
1
For no. 1 it is (Fe) it could also be Na sodium but it will be dangerous.
For no. 2 it is Cl(Z=17)
For no. 3 it is smelting (thanks leonaidas23)
For no. 2 it is Cl(Z=17)
For no. 3 it is smelting (thanks leonaidas23)
durekhan123:
sorry u answer late
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