Math, asked by himarim30, 9 months ago

The method of doing this question a man spends 3/8 of his money and still has Rs.720 left with him. How much money did he have at first.

Answers

Answered by Anonymous
1

\huge{\mathcal{Question :- }}

The method of doing this question a man spends 3/8 of his money and still has Rs.720 left with him. How much money did he have at first.

\huge{\mathcal{Solution :- }}

let,

  • the money he have first be rs x

\huge{\mathcal{Given :- }}

  • 3/8 of x he spent and left 720

now ,

→ x - 3x/8 = 720

→ (8x-3x)/8 = 720

→ 5x/8 = 720

→ 5x = 5760

→ x = 1152

\huge{\mathcal{Hence:-}}

  • he had 1152 rupees first .

  • verification ;-

◆ 1152 - 3/8×1120

◆ 1152 - 3 × 140

◆ 1152 - 420

◆ 720

  • V E R I F I E D
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