the mid point of the line segment joining the points (-6,5) and (-2,3)is (a÷3, 4)then a=
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7
suppose,
(-6,5)=(x1,y1)
(-2,3)=(x2,y2)
(a/3,4)=(x,y)
by midpoint formula,
x=x1+x2÷2
a/3=-6+(-2)÷2
2a/3=-6-2
2a=-8×3
a=24/2
a=12
therefore the value of a is 12
(-6,5)=(x1,y1)
(-2,3)=(x2,y2)
(a/3,4)=(x,y)
by midpoint formula,
x=x1+x2÷2
a/3=-6+(-2)÷2
2a/3=-6-2
2a=-8×3
a=24/2
a=12
therefore the value of a is 12
Answered by
1
Given points (-6,5),(-2,3)
Midpoint of the given line segment =(a+3,4)
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