Question

The mid value of a class interval is 42.if the class size is 10 find the upper and lower limit of the class.

Answer 1

let x be the lower limit and y be the upper limit
then/
         x+y/2=42
         x+y=84....(1)
         x-y=10(....2)
                 by adding these two equations, we get 
                        x=47 and y = 37

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