Question

the mid value of class interval is 42 if the class size is 10 then upper and lower limits of the class are?​

Answer 1

Step-by-step explanation:

let the upper limit and lower limit be x and y

x+y/2=42

x+y=84.........1

according to question

x-y=10...........2

1and2

2x=94

therefore x=47

And ,47-y=10

y=37

• required class interval=37-47

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