Question

the middle digit of a number between 100 and 1000 is 0, the sum of the other digits is 11.if the digits be reversed ,the number so formed exceeds the original number by 495. find the number

Answer 1

let the number be x0y, x+y=11
100x+y=100y+x+495
99x-99y=495
x-y=495/99
x-y=5
x+y=11
2x=16
x=8,y=3 number=803