Question

the middle digit of a number between 100 and 1000 is zero and the sum of the Other digit is 11 if the digits are reversed the number so formed exceeds the original number by 495 find it​

Answer 1

Answer:

original number is 308

Step-by-step explanation:

continuation,

given,

x+y=11-©

according to the problem,

100x+y-100y-x=495

99x-99y=495

=>99(x-y)=495

=>x-y=495/99

=>x-y=5-®

=>®+©

=>x+y+x-y=11+5

=>2x=16

=>x=8

=>x+y=11

=>8+y=11

=>y=11-8

=>y=3

original number is y0x

= 308

reversed numberis x0y

= 803

HOPE THIS HELPS YOU