Question

The middle term of an finite ap 4,7,10.......118 is

Answer 1

$\tt{\overline{\huge{\underline{\underline{ AnSwEr }}}}}$

a = 4

d = 3

an = 118

$\tt{an = a + [ n - 1 ] d}$

✓ 118 = 4 + [ n - 1 ] 3

✓ 114 = [ n - 1 ] 3

✓ n - 1 = 38

✓ n = 39

Now , n is odd thus , middle term = [ n + 1 ] / 2

✓ n = [ 39 + 1 ] / 2

✓ n = 20

✓ nth term = 4 + 19 × 3 ________ an = a + [ n - 1 ] d

✓ nth term = 4 + 57

$\mathcal{\red{nth term = 61}}$

$\tt{\red{\huge{\underline{\underline{ May}}}}}$ $\tt{\red{\huge{\underline{\underline{ Help }}}}}$