The midpoint of the chord 2x + y – 5 = 0 w.r.t x
^2+y^2=9is
Answers
Answer:
Step-by-step explanation:
Here, AB = 20cm and OC = 24cm
Now,
AC=CB=
2
AB
=10cm (perpendicular drawn from centre of the circle to the chord,bisects the chord)
Then using Pythagorean Theorem:
OA=
(AC
2
+OC
2
)
=
(10
2
+24
2
)
=
676
=26
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Answer:
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