Question

the midpoint of the line segment joining points (-1,-12) and (-1,4) is
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Answer 1

Answer:

The midpoint of the line segment joining points (-1,-12) and (-1,4) is $= ( \frac{ - 13}{2} \: , \: \frac{3}{2} )$

Given:

Given Points are (-1, -12) and (-1, 4)

To Find:

The midpoint of the line segment joining the points (-1,-12) and (-1,4) .

Solution:

$Midpoint \: = (\frac{x_1 + x_2}{2} \: , \frac{y_1 + y_2}{2} )$

$Midpoint \: = (\frac{ - 13}{2} \: , \frac{3}{2} )$

$\therefore \: Midpoint \: = ( \frac{ - 13}{2} \: , \: \frac{3}{2} )$

Few things related to this:

• The coordinates of any point on x-axis is (x, 0).

• The coordinates of any point on y-axis is (0,y).

• Midpoint formula :

$= (\frac{x_1 + x_2}{2} \: , \frac{y_1 + y_2}{2} )$

• Centroid formula :

$= (\frac{x_1 + x_2 + x_3}{3} \: , \frac{y_1 + y_2+ y_3}{3} )$

• Distance formula :

The Distance between two points = $\sqrt{ ( x_2 - x_1 {)}^{2} + ( y_2 - y_1 {)}^{2}}$

Answer 2

Given Question :-

• The midpoint of the line segment joining points (-1,-12) and (-1,4) is

Answer

Given :-

• The line segment joining points A(-1,-12) and B(-1,4)

To Find :-

• Midpoint of AB.

Formula used :-

Midpoint Formula:-

⟼ Let us consider a line segment joining the points

$\sf \: A(x_1,y_1) \: and \: B(x_2,y_2)$

⟼ Let C(x, y) be the midpoint of AB, then coordinates of midpoint C is given by

$\bf \:( x, y) = (\dfrac{x_1+x_2}{2} , \dfrac{y_1+y_2}{2} )$

$\begin{gathered}\Large{\bold{\red{\underline{CaLcUlAtIoN\::}}}} \end{gathered}$

⟼ Let C(x, y) be the midpoint of the line segment joining the points A(-1,-12) and B(-1,4).

⟼ Then, Coordinates of C is given by

$\bf \:( x, y) = (\dfrac{x_1+x_2}{2} , \dfrac{y_1+y_2}{2} )$

where,

$\bf \:x_1 = - 1 ,y_1 = - 12,x_2= - 1 ,y_2=4$

⟼ So, we get

$\bf \:( x, y) = (\dfrac{ - 1 - 1}{2} , \dfrac{ - 12 + 4}{2} )$

$\bf \:( x, y) = ( - 1 , - 4)$

⟼ Hence, the midpoint of the line segment joining points (-1,-12) and (-1,4) is (- 1, - 4)