Question

the milliequivalent in 60 ml of 4.0 M H2SO4 is ​

Answer 1

The number of milliequivalents of sulfuric acid is 480 meq.

Explanation:

Relation between normality and molarity is given by the equation:

$\text{Normality}=n\times \text{Molarity}$

We are given:

Molarity of the solution = 4.0 M

n = n-factor for acids = number of replaceable hydrogen = 2 (for sulfuric acid)

Putting values in above equation, we get:

$N_{H_2SO_4}=2\times 4=8N$

Normality is defined as the number of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Number of miliequivalents}}{\text{Volume of solution (in mL)}}$

We are given:

Normality of the soution = 8 N

Volume of solution = 60 mL

Putting values in above equation, we get:

$8N=\frac{\text{Number of miliequivalents}}{60mL}\\\\\text{Number of miliequivalents}=(8\times 60)=480meq.$

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Answer 2

The Number of milliequivalents is 480

• Normality = Molarity *n , where n is n factor

Molarity of the solution M = 4.0 M

n = n-factor for acids is defined as the number of replaceable hydrogen = 2 (for sulfuric acid)

• Normality is defined as the number of gram equivalents dissolved per liter of the solution.

Normality of the solution = 8 N

Volume of solution = 60 mL

Milliequivalents= Normality x volume(in ml)  = Molarity x n-factor x vol.(in ml)= 8  x  60  = 480 m.eq

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