Question

The minimum age of children to be eligible to participate in a painting competition is 8 years. It is observed that the age of youngest boy was 8 years and the ages of rest of participants are having a common difference of 4 months. If the sum of ages of all the participants is 168 years. find the age of eldest participant in the painting competition ​

Answer 1

Answer:

I hope this is help you

Step-by-step explanation:

168×12=

2

n

(2×8×12+(n−1)4)

2016=

2

n

(192+4n−4)

4032=n(188+4n)

4032=188n+4n

2

4n

2

+188n−4032=0

n

2

+47n−1008=0

∴n=

2a

b±

b

2

−4ac

=

2

47±

47×47−4×1×−1008

=

2

47±

2209+4008

=

2

47±79

=

2

47+79

=

2

126

=63

∴t63=a+(n−1)d

=96+62×4

=96+248

=

12

364

=30.3 years

=30 years 4 months