Question

The minimum distance of any point on the ellipse x2+3y2+4xy=4 from its centre is

Answer 1

Answer:

There are exactly two points on the ellipse(x^2/a^2)+(y^2/b^2)=1, whose distance from its center is same and b equal to 1/? 2(?(a^2+2b^2)). The eccentricity of the ellipse is. ... Note :here vertex has the coordinate (a,0) so its distance from the centre whis has been assumed to be (0,0) is a

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