Question

The minimum refractive index of the prism given below
should be
Kincident ray
45°
emergent
ray
90°
459​

Answer 1

Answer:

Explanation:

ANSWER

Applying snell's law at the two refracting surfaces,

sini=μsinr  

1

​  

 

sine=μsinr  

2

​  

 

Also A=r  

1

​  

+r  

2

​  

 

For no emergent ray, e=90  

∘

 

hence, r  

2

​  

=i  

c

​  

 

Also for there to be no emergent ray in any case, r  

1

​  

 can have the maximum value in the limiting case.

For this to happen, i=90  

∘

 in the case.

hence r  

1

​  

=i  

c

​  

 

hence, A>2i  

c

​ hope it helps