The minimum resistance that csn be obtained by combining 50 resistance each of .25 ohm is ?
Answers
Answered by
0
Answer:
If you put the resistances in series then total resistance will be = 50×0.25 = 12.5 ohm
If you put the resistances in parallel then total resistance will be 1/(50×(1/.25)) = 1/200 = 0.005 ohm
Similar questions