Physics, asked by aa3553161, 7 months ago

The minimum resistance that csn be obtained by combining 50 resistance each of .25 ohm is ?

Answers

Answered by dkchakrabarty01
0

Answer:

If you put the resistances in series then total resistance will be = 50×0.25 = 12.5 ohm

If you put the resistances in parallel then total resistance will be 1/(50×(1/.25)) = 1/200 = 0.005 ohm

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