the minimum value of 35cosec²x + 6sin²x is
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First of all we should talk about the range of cosec x. And sin x ..which are (-°°,-1,]©[1,°°) and. [-1,1] respectively.
Since we are likely to minimise the value of eqn hence minimise the 35 cosec^2x so cosec^2 x is minimum at angle 90.so at 90 degree we have
Cosec ^2x is 1 and sin^2x is also 1 hence answer is 35+6 that is 41
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