The minimum value of f (x)= |x-1| + |x-2| is 1) 1 2) -1 3) 2 4) 3
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f (x)=|x-1|+|x-2|
f (1 2)=|1-1|+|2-2|
f(1 2)=|0|+|0|
f (1 2)=0
f (x)is minimum at (1 2)
f (1 2)=|1-1|+|2-2|
f(1 2)=|0|+|0|
f (1 2)=0
f (x)is minimum at (1 2)
Answered by
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Given equation = f (x)=|x-1|+|x-2|
f (x)=|x-1|+|x-2|
f (1 2)=|1-1|+|2-2|
f(1 2)=|0|+|0|
f (1 2)=0
Answer = (A)
(1 2)
f (x)=|x-1|+|x-2|
f (1 2)=|1-1|+|2-2|
f(1 2)=|0|+|0|
f (1 2)=0
Answer = (A)
(1 2)
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