Math, asked by daivagnamv33, 1 year ago

The minimum value of the polynomial 4x^2-6x+1

Answers

Answered by DelcieRiveria
30

Answer:

The minimum value of the polynomial is -1.25.

Step-by-step explanation:

The given polynomial is

p(x)=4x^2-6x+1

The minimum value of an upward parabola is its vertex.

The vertex of  f(x)=ax^2+bx+c is

(\frac{-b}{2a},f(\frac{-b}{2a}))

a=4,b=-6,c=1

\frac{-b}{2a}=\frac{-(-6)}{2(4)}=\frac{3}{4}=0.75

Substitute x=\frac{3}{4} in the given equation.

p(\frac{3}{4})=4(0.75)^2-6(0.75)+1=-1.25

The vertex of the parabola is (0.75, -1.25). Therefore the minimum value of the polynomial is -1.25.

Answered by vijaymishra47882
3

Answer:

vertex=(0.75,-1.25)

minimum value = -1.25

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