Question

the minute hand of a clock is 10 cm long find the area on the face of the clock described by the minute hand between 8 a.m. and 8.25 A.M

please give me answer

Answer 1

Angle described by the minute hand in 60min= 360
Angle described by the minute hand in 25min= 360/60×25= 150
Therefore,
theta= 150 degree and radius= 10cm
Area swept by the minute hand in 25 minutes=
(πr²ø/360)=22/7×10×10×150/360= 130.9cm²

HOPE IT IS CLEAR..
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Answer 2

Answer:

For

60 min --' 360

25 ----- 360/60×25=150

Area swept =

pi r^2 × ¤/360= 22/7×10×10×150/360=130.9 cm^2

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