Question

The minute-hand of a clock is 10cm long. Find the area of the face of the clock

described by the minute hand between 8AM to 8:25 AM.​

Answer 1

Step-by-step explanation:

Hence, the angle described by the minute hand on the face of the clock between 8:00 AM and 8:25 AM is 130.95 cm²

Angle described by the minute hand in 1 minute =6o (Since in 60 minutes, the angle described is 360o)

Angle described by the minute hand in 25 minutes =25×6o=150o

Area swept by the minute hand in 25 minutes =360oθ×πr2

⇒  Area swept by the minute hand in 25 minutes =360o150o×722×(10)2

⇒  Area swept by the minute hand in 25 minutes =130.95cm2

Answer 2

Answer:

Area swept by the minute hand in 25 minutes = 130.95 cm^2

Step-by-step explanation:

Angle described by the minute hand in 1 minute = 6° ( Since in 60 minutes , the angle described is 360° )

Angle described by the minute hand in 25 minutes = 25 × 6° = 150°

Area swept by the minute hand in 25 minutes :

$\frac{theta}{360} \times \pi {r}^{2}$

$- > \frac{150}{360} \times \frac{22}{7} \times 10 \times 10$

$- > 130.95 {cm}^{2}$

I hope it helps u dear friend ^_^♡♡