The minute hand of a clock is 14 cm long. The
approximate distance covered and displacement
of the tip of the minute hand during the interval
the time changes from 5:05 pm to 7:20 pm.
plz give full explanation.......
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Answer:
Length is 14 cm.
From 5:05 to 6:05,there is one complete rotation.
It means distance in this step is 2πr.
from 6:05 to 7:05,again distance is 2πr.
from 7:05to 7:20,distance is 2πr/4.
(bcz shape is half of a semi circle)
So total distance is 2πr + 2πr +2πr/4
on solving.... distance is equal to 198 cm.
displacement only occured in third step.
therefore.... = 2πr/4
=22cm
hope it helps!
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