the minute hand of a clock is 4 cm long the average velocity of the tip of the minute hand between11:00 am to 11:30 am is
(a)
(b)
(c)
(d)
options are in up please answer
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Answered by
9
length= 4 / 100
= 0.04 m
Velocity from 11: 00 am to 11:30 am
= 0.08 / 1800
= 0.000044 m/s
velocity from 11:00 am to 11: 30 pm
= 0.000044 m/s
avg velocity = 0.000044 m/s
= 0.04 m
Velocity from 11: 00 am to 11:30 am
= 0.08 / 1800
= 0.000044 m/s
velocity from 11:00 am to 11: 30 pm
= 0.000044 m/s
avg velocity = 0.000044 m/s
hamdsome:
what is the option
Answered by
20
The time difference is of 30 minutes , hence the minute hand will cover the displacement equal to the diameter of the clock.
The length of the minute hand is almost as long as the radius of the clock, so
Displacement = 2*4 cm = 8cm = 0.08 m
Time = 30min = 1800 seconds
Velocity = Displacement / Time
= 0.08 / 1800 = 4/9 * 10^-4 = 4.5*10-5 (aprox.) OPTION 2
The length of the minute hand is almost as long as the radius of the clock, so
Displacement = 2*4 cm = 8cm = 0.08 m
Time = 30min = 1800 seconds
Velocity = Displacement / Time
= 0.08 / 1800 = 4/9 * 10^-4 = 4.5*10-5 (aprox.) OPTION 2
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