Question

the minute hand of a clock is 8 cm long .find the area swept by the minute hand between 8:30 and 9:05a.m.

Answer 1

Given
Length of minute hand =8cm

The angle created by minute hand in (8:30-9:05) 35min =35x6=210°

( the minute hand create the angle of 360 in 60 min so in 1 min=6°)



Area swept=
$\frac{ \alpha }{360} \times \pi \: {r}^{2}$

=
$\frac{210 \times 22 \times 8 \times 8}{360 \times 7}$
=
$\frac{3 \times 22 \times 2 \times 8}{9}$
=
$\frac{352}{3} {cm}^{2}$
=117.33cm²

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Answer 2

ANSWER
..........





LENGTH OF THE MINUTE HAND = 8 CM


ANGLE CREATED BY THE MINUTE HAND IN THE 35 MINUTE
= 35 * 6
= 210 °

AREA SWEPT
= a / 360 = π r ^2

=
220 × 22 × 22 × 8 × 8
___________________
360 × 7

=
3 × 22 × 2 × 8
_____________
360 × 7


=

352
___. = cm ^2
3


=

117 .33 cm ^2