the minute hand of the clock is 10cm long find the area of face of the clock described by the minute hand between 9.00am and 9.30 am?
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We can imagine it as a sector and the minute hand is radius of the sector
Radius = 10cm
Angle formed between 9:00Am to 9:30Am =
360° in 60 minutes
6° in 1minute
so in 30 minutes = 6*30 = 180°
Area of the sector = theta/360 *π r^2 = 180/360*22/7*100 = 1100/7 cm^2
Radius = 10cm
Angle formed between 9:00Am to 9:30Am =
360° in 60 minutes
6° in 1minute
so in 30 minutes = 6*30 = 180°
Area of the sector = theta/360 *π r^2 = 180/360*22/7*100 = 1100/7 cm^2
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