Physics, asked by penikalapativishnu, 7 months ago

The molal lowering of vapour pressure of a liquid is 1.008 mm of Hg at in a very dilute solution containing non volatile solute. The vapour pressure of liquid at is of Hg. The value of is (molecular weight of liquid = 18)​

Answers

Answered by tannukumari20120737
1

Explanation:

Molal lowering of vapour presure of liquid is 1.008 mm Hg at 25°C

in very dilute solution. The vapour pressure of liquid at

is 25°C

mm Hg. The value of

X

is (molecular mass of liquid is

18g mol-1

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