The molality of a sulphuric acid solution is 0.6mol/kg. The total weight of the solution which contains 1kg solvent
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Given,
Molality of solution:- 0.6 mol/kg
Weight of solvent = 1kg
We know that ,
Molality of solution=weight of solute/weight of solvent(in kg)
Weight of solute = molality * weight of solvent
Weight of solute = 0.6*1
=0.6kg
Weight 0f solution = Weight of solute+ weight of solvent
= 0.6 + 0.6
=1.2 kg
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