Question

The molality of sulphuric acid solution is 0.2 mol/ kg. calculate the total weight of solution

Answer 1

mass of solute is 19.6 g and the mass of solvent is 1000 g then by adding this 1019.6g

Answer 2

Answer: The total weight of the solution is 1019.6 g

Explanation:

We are given:

Molality of sulfuric acid = 0.2 mol/kg

This means that 0.2 moles of sulfuric acid is present in 1 kg (1000 g) of solvent.     (1 kg = 1000 g)

To calculate the mass of sulfuric acid, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$  

Moles of sulfuric acid = 0.2 moles

Molar mass of sulfuric acid = 98 g/mol

Putting values in above equation, we get:

$0.2mol=\frac{\text{Mass of }H_2SO_4}{98g/mol}\\\\\text{Mass of }H_2SO_4=19.6g$

Total mass of solution = Mass of solute + Mass of solvent

Total mass of solution = 19.6 g + 1000 g = 1019.6 g

Hence, the total weight of the solution is 1019.6 g